CG
cgreen
2012-05-22 22:00 UTC
#1
I’m trying to complete the “Two Man Army” achievement but I’m not for sure how this works with the H mechanic in the expansions. For example, the villain does the hero with the highest hp H minus 2 melee damage. With only having 2 heroes does that mean no damage is given? I know the “two man army” is intended for the base game but I really wanted to try it with Rook City. Thoughts?
BR
broccoli
2012-05-22 22:19 UTC
#2
Yeah, that’s one of those weird things. The game isn’t really intended for 2 heroes. That’s why “Two Man Army” is kind of a one-off challenge. You’re not wrong, the H mechanic works exactly like that (no damage at H - 2), but that should help to make up for the fact that you have less total HP, less ability to deal damage, and the environment and villain go “more often”.
FL
flamethrower49
2012-05-22 22:27 UTC
#3
I recall at one point that Chris mentioned that the H mechanic was specifically intended to mean 3, 4 or 5. I wonder which thread that was in. Possibly the same thread where somebody pointed out that you could just have H equal whatever you want in order to adjust the difficulty to suit your needs.
BR
broccoli
2012-05-22 22:58 UTC
#4
Laf, that’d be me that made the suggestion. This is the thread you’re thinking of http://greaterthangames.info/forum/index.php/topic,445.0.html
FL
flamethrower49
2012-05-22 23:54 UTC
#5
Yeah, that’s the one. Man, whoever made that suggestion was smart. 
KE
ketigid
2012-05-23 01:39 UTC
#6
Well, the Two Man Army was introduced before the H mechanic was introduced. And since the core game was balanced for 4 players, it implied that Two Man Army is meant to be tackled with H = 4.
When I play I’ve kind of house ruled it so that H must equal a minimum of 1. Otherwise two man army does get very easy against RC villains.